Team total points odd/even strategy

The odds that the points scored by a team in a match to be strange or even are the same as the odds of tail and head to come out once we flip the coin, meaning 50%. Especially in sports as basketball the points happen more than one at a time and at which the scores are large. It’s just a game of numbers.
If we all know and we knoe that the true probability for each result is 50% we could use the legislation of binomial distribution to estimate the chances of events to occur in trials.
What I mean is that when a team has 6 consecutive odd points that are complete, the chances that the 7th match the points believed to be odd are 0.062, 62 from 1000. More if a group has 7 consecutive odd total points the chances to get at the 8th are 0.035, 35 from 1000. The probability will not become 0 after 8 or 9 consecutive chances but they are getting more closer to 0. At 35/1000, there nevertheless are opportunities but only 35 at 1000 trilas.
The principal point is that Dallas Mavericks possess 6 consecutive odd total points so if we bet total points for Dallas the chances to lose the wager are 6.2percent and Phoenix Suns have seven successive odd totals so if we will score tonight a complete even the odds to shed will be 3.5%.
I didn’t make any backtesting but it’s pure math so I will take them good bets.

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